Find an equation for the line that passes through the point
(x, y) = (6, −2)
and is parallel to the line
4x − 8y = 3.



Answer :

The equation of the line which is parallel to line 4x-8y=3 and passes through (6,-2) is x-2y=10.

Given that the line passes through point (6,-2) and parallel to line

4x-8y=3.

We are required to find the equation of the line about which the description is given.

Equation is basically the relationship between two or more variables that are expressed in equal to form.It may be linear equation, quadratic equation, cubic equation and many more depending on the power of the variables present in it.

Since the line is parallel to the line 4x-8y=3. So their slopes are equal.

4x-8y=3

4x-3=8y

(4x-3)/8=y

y=x/2-3/8

Slope is 1/2.

The equation will be as under:

y+2=1/2 (x-6)

2y+4=x-6

x-2y=10

Hence the equation of the line which is parallel to line 4x-8y=3 and passes through (6,-2) is x-2y=10.

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