Answer :

MrRoyal

The values of the function are q(2) = 21/4, q(0) = undefined and q(-x) = (4x^2 + 5)/x^2

How to evaluate the function?

The function definition is given as:

q(t) = (4t^2 + 5)/t^2

When t =2, we have:

q(2) = (4 * 2^2 + 5)/2^2

Evaluate

q(2) = (4 * 4 + 5)/4

This gives

q(2) = 21/4

When t = 0, we have:

q(0) = (4 * 0^2 + 5)/0^2

Evaluate

q(0) = (4 * 0 + 5)/0

This gives

q(0) = undefined

When t = -x, we have:

q(-x) = (4 * (-x)^2 + 5)/(-x)^2

Evaluate

q(-x) = (4x^2 + 5)/x^2

Hence, the values of the function are q(2) = 21/4, q(0) = undefined and q(-x) = (4x^2 + 5)/x^2

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The numeric values of the function are given as follows:

  • q(2) = 5.25.
  • q(0) = Undefined.
  • q(-x) = (4x² + 5)/x².

How to find the numeric value of a function?

To find the numeric value of a function, we replace each instance of the variable by the desired value.

In this problem, the function is given by:

[tex]q(t) = \frac{4t^2 + 5}{t^2}[/tex]

When t = 2, the numeric value is:

q(2) = [4(2)² + 5]/2² = 5.25.

When t = 0, the numeric value is:

q(0) = [4(0)² + 5]/0² = Undefined, as division by 0 does not exist.

When t = -x, the numeric value is:

q(-x) = [4(-x)² + 5]/(-x)² = (4x² + 5)/x².

More can be learned about the numeric value of a function at https://brainly.com/question/28276964

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