Answer :
The value of f(x+1) =[tex] {2x}^{2} + 7x + 1[/tex]
How to find the value of f(x+1) ?
An statement, rule, or regulation that establishes the relationship between an independent variable and a dependent variable is known as a function.
A relation between a collection of inputs and outputs is known as a function. A function is, to put it simply, a relationship between inputs in which each input is connected to precisely one output. Each function has a range, codomain, and domain. The usual way to refer to a function is as f(x), where x is the input. A function is typically represented as y = f. (x). The value of the function is f(x).
given that
[tex]f(x) = 2x^2 + 3x -4[/tex]
now we find the value of f(x+1).
so, Put x+1 in place of x to obtain the value of f(x+1).
[tex]f(x + 1) = 2(x + 1) {}^{2} + 3(x + 1) - 4[/tex]
[tex]f(x + 1) = 2( {x}^{2} + 2x + {1}^{2} ) + 3x + 3 - 4[/tex]
[tex]f(x + 1) = 2 {x}^{2} + 4x + 2 + 3x + 3 - 4[/tex]
[tex]f(x + 1) = 2 {x}^{2} + 7x + 5 - 4[/tex]
[tex]f(x + 1) = 2 {x}^{2} + 7x + 1[/tex]
Hence the value of f(x+1) is
[tex]2 {x}^{2} + 7x + 1[/tex]
Learn more about functions, refer:
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