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A solid block of wood of density 0.6gcm^-3weighs 3.06 N in air Determine(A)Volume of the block (b)the volume of the block immersed when placed freely in a liquid of density 0.9gcm^-3?



Answer :

pstnonsonjoku

The volume of the solid is 5.1 * 10^-4 m^3.

What is the volume of the block?

The term density is used to describe the ratio of the mass to the volume of a substance. We now have to find the volume of the substance from the information provided.

Density of the solid = 0.6gcm^-3 or 600 Kg/m^3

Mass of the solid =  3.06 N/10 m/s^2 = 0.306 Kg

Now;

volume = mass/density =  0.306 Kg/ 600 Kg/m^3 = 5.1 * 10^-4 m^3

Given that the force = 3.06 N

Density = 0.9gcm^-3 or 900 Kg/m^3

Then;

Volume = 3.06/900 Kg/m^3 * 10 m/s^2

Volume = 3.04 * 10^-4 m^3

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