The resulting values and function are 2, 8, 20, 3x^2+3x + 2 and 3t^2-9t+8
Functions and values
Given the following equation expressed as;
f(x) = 3x^2-3x+2
We are to find the following function;
a) g(0) = 3(0)^2-3(0) + 2
g(0) = 2
b) g(-1) = 3(-1)^2-3(-1) + 2
g(-1) = 3+3+2
g(-1) = 8
c) g(3)= 3(3)^2-3(3) + 2
g(3) = 27-9+2
g(3) = 20
d) g(-x) = 3(-x)^2-3(-x) +2
g(-x) = 3x^2+3x + 2
e) g(1-t) = 3(1-t)^2-3(1-t) + 2
g(1-t) = 3(1-2t+t^2)-3t+3 + 2
g(1-t) = 3-6t+3t^2-3t+5
g(1-t) = 3t^2-9t+8
Hence the resulting values and function are 2, 8, 20, 3x^2+3x + 2 and 3t^2-9t+8
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