Answer :
The fermentation of glucose, C6H12O6, produces ethyl alcohol, their number of molecules of CO2 form, when 2.00 g of C₂H5OH are produced, which is 3.913 g of ethanol.
Fermentation is a metabolic method that produces chemical adjustments in organic substrates thru the motion of enzymes. In biochemistry, it is narrowly defined as the extraction of electricity from carbohydrates in the absence of oxygen. Fermentation is the technique of sugars being broken down by using enzymes of microorganisms in the absence of oxygen into ethanol. Microorganisms including microorganisms and fungi have particular sets of metabolic genes, permitting them to produce enzymes to interrupt distinct types of sugar metabolites.
calculation;
1 mole of glucose produces 2 mol2 of CO mole of CO2
Mass of 1 mole of glucose = 180
A mole of 1 mole of ethanol = 46g
Since 180 grams of glucose produces = 92 grams of ethanol
92 grams of ethanol = 180 g of glucose
1 gram of C2H5OH = 180/92 g of glucose
∴ 2 g of C2H5OH = 180/92 × 2 g of glucose
= 3.913 g of ethanol
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