If earth's mass were half its actual value but its radius stayed the same, the escape velocity of earth would be:________



Answer :

If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be [tex]V_e = \sqrt{\dfrac{GM}{r}}[/tex].

What is an escape velocity?

The ratio of the object's travel distance over a specific period of time is known as its velocity. As a vector quantity, the velocity requires both the magnitude and the direction. the slowest possible speed at which a body can break out of the gravitational pull of a certain planet or another object.

The formula to calculate the escape velocity of earth is given below:-

[tex]V_e=\sqrt{\dfrac{2GM}{r}}[/tex]

Given that earth's mass was half its actual value but its radius stayed the same. The escape velocity will be calculated as below:-

[tex]V_e=\sqrt{\dfrac{2GM}{r\times 2}}[/tex]

[tex]V_e = \sqrt{\dfrac{GM}{r}}[/tex].

Therefore, If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be [tex]V_e = \sqrt{\dfrac{GM}{r}}[/tex].

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