Between two times, an athletic mouse moves to the right for an unknown distance and then to the left for 2.06
m. Between these two times the mouse has an average speed of 2.93 m/s and an average velocity of 1.18 m/s.
What is the unknown distance that the mouse traveled to the right?
a. 5.419 m
b. 4.403 m
c. 2.951 m
d. 4.838 m



Answer :

The magnitude of the unknown distance is 4.838 m. The correct option is d

What is Average Speed ?

Average speed is the total distance travelled per total time. While average velocity is the total displacement per total time.

Given that an athletic mouse moves to the right for an unknown distance and then to the left for 2.06m. Between these two times the mouse has an average speed of 2.93 m/s and an average velocity of 1.18 m/s.

Let the unknown distance be d

Total distance s = d + 2.06

Speed = s/t

2.93 = ( d + 2.06 ) / t

Make t the subject of the formula

t = ( d + 2.06 ) / 2.93

Total displacement D = d - 2.06

Velocity v = D/t

1.18 = ( d - 2.06 ) / t

t = ( d - 2.06 ) / 1.18

Since t is the same,

( d - 2.06 ) / 1.18 = ( d + 2.06 ) / 2.93

Cross multiply

2.93( d - 2.06 ) = 1.18( d + 2.06 )

2.93d - 6.0358 = 1.18d + 2.4308

Collect the like terms

2.93d - 1.18d = 2.4308 + 6.0358

1.75d = 8.4667

d = 8.4667 / 1.75

d = 4.838 m

Therefore, the magnitude of the unknown distance that the mouse traveled to the right is 4.838 m. The correct option is d which is 4.838 m

Learn more about Average Velocity here: https://brainly.com/question/6504879

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