Answer :
Zn2+ must be reduced to Zn with a charge of 1585.26 coulomb.
Steps
The reaction of Zn reduction can be expressed as follows:
Zn²⁺ + 2e⁻ → Zn (s)
Molar mass of Zn = 65.39 g
The equivalent of Zn²⁺ has been:
Equivalent = atomic mass/equivalent weight
Equivalent Zn²⁺ = 65.39/32.69
Equivalent Zn²⁺ = 2 mol
1 equivalent = 1 F charge used
2 mol equivalent = 2 F charge used
Charge in coulomb can be given as:
1 Faraday = 96500 coulomb
2 F = 96500 * 2 coulomb
2 F = 1,93,000 coulomb
The amount of zinc to be deposited in moles is:
Moles equal weight x molar weight.
Molecular weight: 0.5371 g/65.39 g/mol
Mol = 0.00821 moles.
As a result, the following charge was used to deposit 0.00821 mol:
Charge is equal to 0.00821 x 1,93,000 coulomb.
Charge equals 1585.26 coulombs.
The Zn2+ was converted to Zn using a 1585.26 coulomb charge.
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