The distance would change by 62.85
If the radius of the small gear is 1.5 inches and the radius of the large gear is 4.5 inches, we have;
Number of rotation of the small gear for each rotation of the large gear = 3 rotations
We have the number of rotation of the wheel = 3
Then we have to solve for distance
= 3 × 2 × π × 10 inches = 60*π inches
The difference in distance = 60*π inches - 40*π inches =
20·π inches
= 20 x 22/7
= 62.85
The distance traveled by the bicycle increases by 62.85 inches
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