Answer :

Using the normal distribution, there is a 0.2389 = 23.89% probability of sampling someone with a z-score lower than z = -0.71.

Normal Probability Distribution

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

From the second bullet point, the probability of sampling someone with a z-score lower than z = -0.71 is the p-value of z = -0.71, hence it is of 0.2389 = 23.89%.

More can be learned about the normal distribution at https://brainly.com/question/24537145

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