Answer :
0.441 J of energy will be transported across a 1.00-cm2 area per hour by an EM wave whose electric field has an RMS strength of 21.5 v/m
Energy transfer across area = 1 [tex]cm^{2}[/tex] = [tex]10^{-2}[/tex] [tex]m^{2}[/tex]
since , Current = [tex]E_(rms)^{2}[/tex]/ c * mu0
c = speed of light = 3 * [tex]10^{8}[/tex] m/s
mu0 = 4π * [tex]10^{-7}[/tex]
I = [tex](21.5)^{2}[/tex] * 3600 * [tex]10^{-4}[/tex] / 3 * [tex]10^{8}[/tex] * 4 * 3.14 * [tex]10^{-7}[/tex]
= 0.441 J
hence , 0.441 J of energy will be transported across a 1.00-cm2 area per hour by an EM wave whose electric field has an RMS strength of 21.5 v/m
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