The mean, variance, and standard deviation are 1, 8,33 and 2.89
How to find the mean, variance, and standard deviation?
The distribution is given as:
[a, b] = [-4, 6]
The mean is calculated as;
Mean = (a + b)/2
So, we have
Mean = (-4 + 6)/2
Evaluate
Mean = 1
The variance is calculated as;
Var = (b - a)^2/12
So, we have
Var = (6 + 4)^2/12
Evaluate
Var = 8.33
The standard deviation is calculated as;
SD= sqrt(Var)
So, we have
SD = sqrt(8.33)
Evaluate
SD = 2.89
Hence, the mean, variance, and standard deviation are 1, 8,33 and 2.89
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