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A falling object travels a distance given by the formula =4+22, where is measured in feet and is measured in seconds. how many seconds will it take for the object to travel 58 feet? round the answer to 4 decimal places.



Answer :

ayfat23

The time it will take for  falling object travels a distance given by the formula =4+22+16t^2 , where is measured in feet and is measured in seconds to travel 58 feet is 1.53532s

How can this be calculated?

d =4t+22t^2

We want to find the value of t, such that d = 58ft

Then we  we solve the equation

58 = 4*t + 22*t^2

We can rewrite this as:

-22*t^2 - 4*t  + 58 = 0.

solving using quadratic formular we have,

x=−1.71714

x=1.53532s

Therefore, The time it will take for  falling object travels a distance given by the formula =4+22+16t^2 , where is measured in feet and is measured in seconds to travel 58 feet is 1.53532s

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