A 2.0-kg block travels around a 0.50-m radius circle with an angular velocity of 12 rad/s. the magnitude of its angular momentum about the center of the circle is:_________

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25-08-2022
Physics

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A 2.0-kg block travels around a 0.50-m radius circle with an angular velocity of 12 rad/s. the magnitude of its angular momentum about the center of the circle is:_________

Answer :

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Tutorconsortium367 Tutorconsortium367 · Answer 1 · 2022-08-31T02:59:13-04:00

Angular momentum about the center of the circle is L = 6 J.s.

What is Angular momentum?

The rotational equivalent of linear momentum in physics is called angular momentum, also known as moment of momentum or rotational momentum. Because it is a conserved quantity—the total angular momentum of a closed system stays constant—it is significant in physics. Both the direction and the amplitude of angular momentum are conserved.

We can calculate angular momentum by the formula L = r*p or L = mvr.

L = angular momentum = ?

m = mass of block = 2 kg

r = radius of circle = 0.5 m

ω = angular speed = 12 rad/s

v = linear velocity = rω = (0.5 m)(12 rad/s) = 6 m/s

Therefore,

L = (2 kg)(6 m/s)(0.5 m)

L = 6 J.s

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