If the frequency of the motion of a simple harmonic oscillator is doubled, by what factor does the maximum speed of the oscillator change? group of answer choices



Answer :

time period = 1/f = 1/32.8 x 103 = 3.05 x 10-5 = 30.5 x 10-6 sec  speed of the oscillator change,

maximum speed is given as

Vmax = A (2\pif)                              A-- amplitude   , f = frequency

from the formula, we can see that Vmax is directly proportional to 'f', so when 'f' is doubled, Vmax gets doubled  or change by a factor of 2

frequency = no of beats / time

f = 76/60 = 1.27 Hz

time period = 1/f = 1/32.8 x 103 = 3.05 x 10-5 = 30.5 x 10-6 sec

An oscillator is a mechanical or electronic device that operates on the principle of vibration. That is periodic fluctuations between two things are based on changes in energy. Computers, watches, radios, and metal detectors are among the many devices that use oscillators.

High-frequency VCOs are usually made by adding a varactor diode to the tank circuit or resonator of the oscillator circuit. Changing the varactor's DC voltage changes its capacitance, which changes the resonant frequency of the tuned circuit.

Learn more about oscillator change here:

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