Answer :
-20v²⁵ is the value obtained when we multiply 4v² with (-5v²³). This can be obtained by multiplying the constants and multiplying the variables by adding the exponents using product rule of exponents.
Multiply 4v² with (-5v²³):
-20v²⁵ is the value obtained when we multiply 4v² with (-5v²³). This can be obtained by multiplying the constants and multiplying the variables by adding the exponents using product rule of exponents.
Multiply 4v² with (-5v²³):
This can be solved using rules of exponents are,
- Zero exponent rule, a⁰ = 1
- Product rule, [tex]a^{m}.a^{n}=a^{m+n}[/tex]
- Power of a power rule, [tex](a^{m})^{n}=a^{mn}[/tex]
- Power of a product rule, [tex](ab)^{m}=a^{m}.b^{m}[/tex]
- Negative exponent rule, a⁻ⁿ = 1/aⁿ
- Quotient rule, [tex]\frac{a^{m}}{a^{n} } =a^{m-n}[/tex]
Here in the question it is given that,
- 4v²
- -5v²³
We have to find the value when 4v² is multiplied by (-5v²³).
4v²(-5v²³)
By multiplying the constants we get,
⇒ -20[v² × v²³]
By multiplying the variables using product rule of exponents we get,
⇒ -20[v²⁺²³] = -20[v²⁵]
Hence -20v²⁵ is the value obtained when we multiply 4v² with (-5v²³).
Learn more about exponent rules here:
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