3x² - 8(y + 2) 2y for x = 8 and y = -2 is equal to -48.
The provided equation is a quadratic equation of the type [tex]ax^2+bx+c[/tex], and as such, we must find a solution for the unknown term x. One approach to discover the roots of the given quadratic equation is to complete the square. A quadratic equation is a polynomial equation with degree equal to two.
Finding the values of a, b, and c beforehand is one of the simpler approaches to solve the equation using the formula. Directly entering the values into the calculation raises the possibility of making sign-related mistakes. Observe "[tex]b^2[/tex]"
" denotes the square of each b.
its sign included.
[tex]3x^2-8(y+2)/2y=3x^2-8y-16/2y[/tex]
[tex]3x^2-8y-16/2y[/tex]
Substituting the value of x=8 and y=-2
[tex]3(8)(8)-8(-2)-16/2(-2)[/tex]
[tex]=192+16-16/-4[/tex]
[tex]=192/-4[/tex]
[tex]=-48[/tex]
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