A physics student measured the period of a pendulum in his school's physics lab and recorded results for five trials (4.6s, 4.5s, 4.8s, 4.4s, 4.7s). what is the average deviation for these results?



Answer :

We have the average deviation of set of data 4.6, 4.5, 4.8, 4.4, 4.7 is

σ = 0.12

We have to find average deviation of the time period of pendulum in five different trials (4.6s, 4.5s, 4.8s, 4.4s, 4.7s)

Mean is the average of the given numbers and is calculated by dividing the sum of given numbers by the total number of numbers. It is one of the measures of the central tendency.

Average Deviation of set of observations is calculated by computing the mean and then the specific distance between each observation and that mean.

Total number of observations, N = 5

Sum of observations = 4.6 + 4.5 + 4.8 + 4.4 + 4.7 = 23

[tex]Mean, x = \frac{Sum of observations}{Total no of observations } = \frac{23}{5}[/tex]

Mean = 4.6

[tex]Average Deviation = \frac{|4.6-4.6| + |4.5-4.6| + |4.8-4.6| + |4.4-4.6| + |4.7-4.6|}{5}[/tex]

[tex]= \frac{0 + 0.1 + 0.2 + 0.2 + 0.1}{5}[/tex]

[tex]= \frac{0.6}{5}[/tex]

= 0.12

The Average Deviation for  the observation of time period of pendulum is 0.12.

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