A stock solution of magnesium chloride has a concentration of 120 mgml. how many milliliters of the stock solution are required to prepare 1.5 l of 25 mgml solution?



Answer :

312.5 mL of magnesium chloride stock solution is needed to prepare 1.5 L of 25 mg/mL solution.

This type of chemical process is called dilution. It is the addition of water into a small amount of a concentrated solution or a stock solution to make it less concentrated. In this problem, the equation below is used.

(Concentration of stock solution)(Volume of stock solution needed)=(Resulting concentration of solution)(Resulting volume of solution)

For easier writing of the equation, subscript 1 can be assigned to the concentrated solution and subscript 2 for the diluted solution.

C1*V1=C2*V2

Substituting the given to the formula:

(120 mg/ml)*(V1)=(25 mg/ml)*(1.5 L)

V1= 0.3125 L

V1= 312.5 ml

For more information regarding the dilution process, please refer to the link https://brainly.com/question/6692004.

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