Answer :
To produce ClO⁻ and ClO₃⁻, the mole ratio of Cl₂ is 1 :2 and 1 : 2.
What is Disproportionate reaction ?
The reaction for disproportionate of Cl₂ in basic medium to produce ClO⁻ and ClO₃⁻ is:
Cl₂ (g) + 2OH⁻ (aq) → Cl⁻(aq) + ClO⁻ (aq) + H₂O(l)
3Cl₂ (g) + 6OH⁻ (aq) → 5Cl⁻ (aq) + ClO₃⁻ (aq) + 3H₂O (l)
When ratio of Cl₂ is 1: 2 then ClO⁻ is produced. Ratio is 3 : 6 then ClO₃⁻ is produced.
To produce ClO⁻ ; the mole ratio of Cl₂
= [tex]\frac{1}{2}[/tex]
= 1 : 2
To produces ClO₃⁻ ; mole ratio of Cl₂
= [tex]\frac{3}{6}[/tex]
= 1 : 2
Thus from the above conclusion we can say that To produce ClO⁻ and ClO₃⁻, the mole ratio of Cl₂ is 1 :2 and 1 : 2.
Learn more about the Chlor-Alkali Process here: https://brainly.com/question/11945425
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