A balloonist begins a trip in a helium-filled balloon in early morning when the temperature is 15°C. By mid-afternoon, the temperature is 30.°C. Assuming the pressure remains at 1.00 atm, for each mole of helium, calculate the following:
(d) The heat (q) transferred (in J)



Answer :

The heat (q) transferred is 311.775J.

The process of moving heat from one thing at a higher temperature to another object at a lower temperature is known as heat transfer. As a result, heat is a measure of the kinetic energy that the particles in a system have. where Q is the amount of heat that is transported to or from the item, m is the object's mass, C is the material's specific heat capacity, and T is the resultant temperature change of the object.

At constant pressure, the change in enthalpy represents the amount of heat that is transported from a system to its surroundings or vice versa. The total of heat transferred and work performed represents the change in the internal energy of a system.

Cp =5/2 R

Enthalpy change= nCpΔT

Enthalpy change= 1×5/2 R × (T2 − T1)

Enthalpy change=  [tex]\frac{5*8.314}{2}[/tex] × 15

Enthalpy change = 311.775 J

ΔH=qp

As the pressure is constant enthalpy change will be equal to the heat transferred (Q) i.e, 311.775 J

To know more about enthalpy change refer to:   https://brainly.com/question/4526346

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