Answer :
The volume of cold water is 53 mL.
Given,
Temperature of unknown volume of water = 18.3°C
The final temperature of water = 23.5°C
Volume of water at 35°C = 24.4 mL
As we know that,
density of water = 1g/mL.
Density = mass/ volume
1 = mass/ 24.4 mL
mass of water = 24.4 g
The value of temperature change for cold water = final temperature – initial temperature
= 23.5 - 18.2
∆T = 5.3°C
As we know that,
Qc = m × c × ∆T
By substituting all values , we get
Qc = m × c × 5.3 ------ (1)
The value of temperature change for hot water=
final temperature – initial temperature
= 35 - 23.5
∆T = 11.5
Qh = 24.4 × c × 11.5 --------(2)
Given,
mass of hot water at 35°C = 24.4 g
From equation (1) and (2), we calculated that
mass of cold water at 18.2°C = 53 g.
Density = mass/volume
1 = 53/ volume
Volume = 53 mL.
Thus, we calculated that the volume of cold water is 53 mL.
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