Answer :
At constant temperature, a sample of helium gas expands from 922 mL to 1.14 L against a pressure of 2.33 atm. w (in J) done by the gas (1 J = 9.87X10⁻³ atm·L).
work done with the aid of a device is defined as the amount of power exchanged between a system and its environment. work is absolutely ruled by way of outside factors which include an outside pressure, strain or quantity or exchange in temperature and many others.
[tex]P_{ext}[/tex]= 2.33atm
[tex]V_{initial}[/tex]=922ml = [tex]\frac{922}{1000}[/tex] L = 0.922L
[tex]V_{final}[/tex]= 1.14L
w = - [tex]P_{ext}[/tex] × ([tex]V_{final}[/tex] - [tex]V_{initial[/tex])
w = - 2.33 × ( 1.14 - 0.922)
w = - 2.33 × 0.218
w = - 0.50794 atm-L
w = - (0.50794 × 101.3) J
w = - 51.454322 J
w = - 51.45 J
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