Answer :
This question is an example of Charles' law.
Charles' law- This law states that at constant pressure, the volume of a given amount of gas is directly proportional to the temperature (in kelvin K). Therefore, with the increase in volume of the gas, the temperature increases whereas with decrease in volume of the gas, the temperature decreases.
Formula of Charles' law-
V₁/T₁=V₂/T₂
where,
V₁= Initial volume
V₂= Final volume
T₁= Initial temperature
T₂= Final temperature
Given,
V₁= 93mL
T₁ = 144°C + 273.15 = 417 K
T₂ = -22°C + 273.15 = 251 K
Therefore, V₂ = V₁T₂/T₁
= (93mL × 251 K)/ 417 K = 56 mL
Learn more about Charles' Law here-
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