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The minerals hematite (Fe₂O₃) and magnetite (Fe₃O₄) exist in equilibrium with atmospheric oxygen:4Fe₃O₄(s) + O₂(g) ⇄ 6Fe₂O₃(s) Kp = 2.5×10⁸⁷ at 298K (c) Calculate Kc at 298 K.



Answer :

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Kc at 298K is Kc = 1 × 10^84.

The relation between Kp and Kc is

      Kp = KcRT

The value of Kp is known

We can calculate the value of Kc with this

R =  8.3145 J mol^−1 K^−1 .

T = 298K

      Kp = KcRT

      2.5×10⁸⁷ = Kc × 8.3145 × 298

      2.5×10⁸⁷ = Kc × 2477.572

      Kc = 1 × 10^84

The ratio of the equilibrium concentrations of products over the equilibrium concentrations of substances, or the equilibrium constant, Kc.

To learn more about Kc click the given link

https://brainly.com/question/25651917

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