Propane is widely used in liquid form as a fuel for barbecue grills and camp stoves. For 85.5 g of propane, calculate
(b) grams of carbon.



Answer :

Propane is widely used in liquid form as a fuel for barbecue grills and camp stoves. For 85.5 g of propane, grams of carbon is 3.55 x 10²⁴ molecules.

What is the calculations?

Given:

moles of propane = 5.9 moles

molecules of propane (C₈H₈) = ?

Formula: no. of moles = no. of molecules / Avogadro's number

We use:

no. of molecules = no. of moles x Avogadro's number . . . . .  (1)

Where,

Avogadro's number = 6.022 x 10²³

Put values in equation (1)

no. of molecules =5.9 mol x 6.022 x 10²³ (molecules/mol)

no. of molecules = 3.55 x 10²⁴ molecules

So, There are 3.55 x 10²⁴ molecules in 5.9 moles of propane

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