Answer :
The correct option is Not Available.
The Hardy-Weinberg Law of Population and Genetics states that p²+2pq+q²=1 and p+q=1 where p is the population's frequency of the dominant allele and q is the population's frequency of the recessive allele.
p² = proportion of homozygous dominant people
q² = the proportion of homozygous recessive people
2pq = the proportion of heterozygous people
Given,
2pq = 0.56,
we may obtain y=0.28/p (the frequency of the recessive allele) by finding 'p' recall, p+q=1, and p=1-q.
By replacing, we obtain q=0.28/(1-q), which is equivalent to q(1-q)=0.28 andq²-q+0.28 (quadratic equation)
Finding "q" by solving this yields two hypothetical values for q.
There isn't a fictitious solution among the alternatives, hence there isn't a solution.
Learn more about the Hardy-weinberg equation with the help of the given link:
https://brainly.com/question/12143126
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