In peas, a gene controls flower color such that R= purple and r= white. In an isolated pea patch, there are 36 purple-flowering plants and 64 white-flowering plants. Assuming HardyWeinberg equilibrium, what is the value of q for this population? (A) 0.36 (B) 0.64 (C) 0.75 (D) 0.80



Answer :

The correct option is (D) 0.80

Assuming Hardy-Weinberg equilibrium, the value for q = 0.80

p² + 2pq + q² = 1 is the Hardy-Weinberg equation. This equation is crucial theoretically because it shows that if a certain amount of alleles are present and nothing else alters the gene pool, the next generation will inherit the results of your issue.

Purple outshines white as the most common color in flowers. The genotype "rr" would be present in plants with white blossoms. A total of 100 plants, including 64 white-flowering plants and 36 purple-flowering plants.

The presented data indicate that the homozygous recessive plant (q2) percentage in the population is 64/100, or 0.64.

Therefore, (q)= square root of 0.64 = 0.80 is the frequency of the recessive allele "r" in the population.

Learn more about the Hardy-Weinberg equation with the help of the given link:

https://brainly.com/question/12143126

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