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Suppose 64 % of a remote mountain village can taste phenylthiocarbamide (PTC) and must, therefore, have at least one copy of the dominant PTC taster allele. If this population conforms to Hardy-Weinberg equilibrium for this gene, what percentage of the population must be heterozygous for this trait? (A) 16 % (B) 32 % (C) 40 % (D) 48 %



Answer :

The correct option is (D) 48%

48% of the population must be heterozygous for this trait.

Let's assign,

T = Dominant allele

t = Recessive allele

Using the Hardy-Weignburg equation, p²+2pq+q² = 1

p² + 2pq = 0.64

q² = 1 - 0.64 = 0.36

q = 0.6

Recall that, p+q = 1

p = 1 - 0.6 = 0.4

To determine the population with the heterozygous trait = 2pq

2 X 0.4 X 0.6= 0.48

This suggests that 48% of the population possesses the gene that allows them to taste phenylthiocarbamide.

Learn more about the Hardy-weinberg equilibrium with the help of the given link:

https://brainly.com/question/14669053

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