Black fur in mice (B) is dominant to brown fur (b) . Short tails (T) are dominant to long tails
(t). What fraction of the progeny of crosses Bb Tt × BB tt will be expected to have black fur and long tails? (A) 1 / 16 (B) 3 / 8 (C) 1 / 2 (D) 9 / 16



Answer :

Black fur in mice (B) is dominant to brown fur (b). Short tails (T) are dominant to long tails (t). (C) 1 / 2 of the progeny of crosses Bb Tt × BB tt will be expected to have black fur and long tails.

Crosses among individuals differing in two traits is known as a dihybrid cross.

Mice with genotype Bb Tt will form 4 types of gametes, namely, BT, Bt, bT and bt, while those containing the genotype BB tt will produce gametes with 'Bt' combination.

On crossing Bb Tt × BB tt, we will get 16 possible genotypes. However, only 8 offspring will have black fur (B) and long tails (t) with the possible genotypes- BBtt and Bbtt.

Thus, on dividing 8 by 16 we get 1/2.

To learn more about dihybrid cross here

https://brainly.com/question/1185199

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