Answer :
MgF₂ has one magnesium ion and two fluoride ions per unit of magnesium fluoride. The percent mass of elements of MgF2 are 39.012 of Mg and 60.989 of F.
- Magnesium fluoride is a binary ionic compound. It is comprised of two fluorine and one magnesium atom. Since it is an ionic compound, it is made up of anions and cations.
- Magnesium is metal and has a much lower electronegativity than fluorine. Hence, this compound consists of two fluoride anions and a magnesium cation.
- Mass percent of an element in a compound ⇒
( mass of the elements/ molar mass of compound) × 100
Molar mass of MgF₂, is 62.301g/mol (24.305+2×18.998)
Mass Percent of Mg =( 24.305 / 62.301) × 100
= 39.012%
Mass percent of F = (18.998×2 / 62.301) ×100
= 60.989%
Thus we can conclude as :
Element Atomic Number of Atoms Mass Percent.
mass
Mg 24.305 1 39.012%
F 18.998 2 60.989%
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