Answer :

MgF₂ has one magnesium ion and two fluoride ions per unit of magnesium fluoride. The percent mass of elements of MgF2 are 39.012 of Mg and 60.989 of F.

  • Magnesium fluoride is a binary ionic compound. It is comprised of two fluorine and one magnesium atom. Since it is an ionic compound, it is made up of anions and cations.
  • Magnesium is metal and has a much lower electronegativity than fluorine. Hence, this compound consists of two fluoride anions and a magnesium cation.
  • Mass percent of an element in a compound ⇒

( mass of the elements/ molar mass of compound) × 100

Molar mass of MgF₂, is 62.301g/mol (24.305+2×18.998)

Mass Percent of Mg =( 24.305 / 62.301) × 100

                                  = 39.012%

Mass percent of F   = (18.998×2 / 62.301) ×100

                                  = 60.989%

Thus we can conclude as :

Element      Atomic        Number of Atoms    Mass Percent.

                    mass

  Mg            24.305                 1                      39.012%

   F               18.998                2                      60.989%

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