The sum of IE₁ through IE₄ for Group 4A(14) elements shows a decrease from C to Si, a slight increase from Si to Ge, a decrease from Ge to Sn, and an increase from Sn to Pb.(c) Which group might show even greater deviations?

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23-08-2022
Chemistry

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The sum of IE₁ through IE₄ for Group 4A(14) elements shows a decrease from C to Si, a slight increase from Si to Ge, a decrease from Ge to Sn, and an increase from Sn to Pb.(c) Which group might show even greater deviations?

Answer :

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rafikiedu08 rafikiedu08 · Answer 1 · 2022-08-30T05:44:45-04:00

The correct answer is 3A (13) even greater deviation in ionization energy.

The elements of the group 3A (13) show greater deviation in the trend in ionization energy. This is because of the presence of single electron in p orbital and this electron receives no shielding effect from other p electrons.

What is ionization energy?

The degree of problem or difficulty involved in removing an electron from an atom or an ion can be described as the ionization energy. It can alternatively be described as an atom's or an ion's propensity to give up an electron. Typically, electron elimination takes place in the chemical types' ground states. The least amount of energy needed for an electron in a vaporous atom or ion to expend in order to escape the influence of the nucleus is another technical approach to define the ionization energy.

To learn more about ionization energy refer the above link:

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