The new dimensions of the rectangular garden when [tex]1\frac{5}{8}[/tex] feet is added to
all the sides of the garden are [tex]14\frac{1}{8}[/tex] feet by [tex]18\frac{3}{8}[/tex] feet .
It is given in the question that the the dimensions of the rectangular
garden are [tex]12\frac{1}{2}[/tex] feet by [tex]16\frac{3}{4}[/tex] feet . Also [tex]1\frac{5}{8}[/tex] feet is added to all the sides of
the rectangular garden.
We have to find the new dimensions of the rectangular garden.
We know that,
If [tex]1\frac{5}{8}[/tex] feet is added to the side with dimension [tex]12\frac{1}{2}[/tex] feet , we will get,
[tex]12\frac{1}{2}+1\frac{5}{8}=\frac{25}{2}+\frac{13}{8}=\frac{100+13}{8}=\frac{113}{8}=14\frac{1}{8}[/tex] feet.
Also, we know that,
If [tex]1\frac{5}{8}[/tex] feet is added to the dimension [tex]16\frac{3}{4}[/tex] feet, we will get,
[tex]16\frac{3}{4}+1\frac{5}{8}=\frac{67}{4}+\frac{13}{8}=\frac{134+13}{8}=\frac{147}{8}=18\frac{3}{8}[/tex] feet.
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