Answer :
The radius of the circle is given by:
square root ( 34 - 6h - 10k + h² + k² ).
If center is (0,0), r = 5.83.
Given,
The circle passes through the point (-3,5).
We need to find the radius of the circle.
What is the equation of the radius of a circle passing through a point?
The equation is given by:
r = [tex]\sqrt{(x - h)^{2} + (y - k)^{2} }[/tex]
Where (x,y) is the point that the circle passes and (h,k) is the point at the center of the circle.
We have,
(x,y) = (-3,5)
So,
Radius = square root { (-3 - h )² + ( 5 - k )² }
= square root ( 9 - 6h + h² + 25 - 10k + k² )
= square root ( 34 - 6h - 10k + h² + k² )
If we consider the center of the circle is (0,0)
we have,
Radius = square root { (-3-0)² + (5-0)²}
= square root {9 + 25}
= square root 34
= 5.83
Thus the radius of the circle is given by:
square root ( 34 - 6h - 10k + h² + k² ).
If center is (0,0), r = 5.83
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