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For a certain 12- v car battery ( e = 12.6 v ), the terminal voltage drops to 8.34 v when the starter draws 86.2 a . what is the internal resistance of the battery?



Answer :

The internal resistance of the battery is 0.049 [tex]\ohm[/tex]Ω

How can we calculate the value of the internal resistance?

To calculate the internal resistance we are using the formula,

E = V + Ir

where,

E = Emf of the car battery.

V = The terminal voltage drops of the car battery.

I = The current floes through the battery.

Here,

E = 12.6 V.

V = 8.34 V.

I = 86.2 A.

We have to calculate the value of internal resistance = r

Now we put the known values in the above equation we get,

E = V+Ir

Or, Ir= E-V

Or, r= [tex]\frac{E-V}{I}[/tex]

Or, r= [tex]\frac{12.6-8.34}{86.2}[/tex]

Or, r = 0.049 [tex]\ohm[/tex]Ω

So from the above calculation we can conclude that the internal resistance of the battery is [tex]\ohm[/tex]0.049Ω

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