An inductor has a 46.0 reactance at 60.0 hz. what will be the maximum current if this inductor is connected to a 50.0 hz source that produces a 105 v rms voltage?



Answer :

The maximum current if this inductor is connected to a 50.0 hertz source that produces a 105 v rms voltage is 3.87A

X= ωl

where,

X is inductive reactance

ω is thee angular  frequency

L is the inductance

therefore,

46= 2π60.L                   eq-1

and

X° is inductive reactance when 50 hz source is used

X°=2π50.L                    eq-2

dividing eq 2 by eq 1 we get

X°=38.33 Ω

maximum current (I°) = maximum voltage divided by  inductive reactance

I°=√2Vrms/38.33

I°=3.87A

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