If the temperature of the flexible container which has 5L of nitrogen gas is increased from 298 K to 333 K is 5.59 L
To solve the question, let's understand Charles' law which states that - [tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]
Here,
V₁ is the initial volume, T₁ is the initial temperature, V₂ is the new volume, and T₂ is the new temperature
Initial volume (V₁) = 5 L
Initial temperature (T₁) = 298 K
New temperature (T₂) = 333 K
New Volume (V₂) =?
We know that, [tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]
=> [tex]\frac{5}{279} = \frac{V_{2}}{333}[/tex]
=> 298 × V₂ = 5 × 333
Dividing both sides by 298, we get
V₂ =[tex]\frac{5*333}{298}[/tex]
V₂ = 5.59 L
To learn more about Charle's Law, head here
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