Answer: [tex]y=\frac{7}{3}x[/tex]
Step-by-step explanation:
[tex]m=\frac{-14-0}{-6-0}=\frac{14}{6}=\frac{7}{3}[/tex]
Since the line passes through the origin, the equation is [tex]y=\frac{7}{3}x[/tex]
The function rule for the line that passes through the origin (0,0) and the point (-6,-14) is 7x - 3y = 0.
According to the given question.
We have a two points (0, 0) and (-6, -14)
Since, we have to find a function rule for the line that passes through the origin (0,0) and the point (-6,-14).
As we know that " a function rule is a relationship between the dependent and independent variables in the form of an equation".
So, basically we have to find the equation of line which passes throgh the point (0, 0) and (-6, -14).
Therefore, the equation of line which passes through (0, 0) and (-6, -14) is given by
( y - 0) = ((-14 - 0)/(-6 - 0))( x - 0)
⇒ y = (-14/-6)(x)
⇒ y = 14/6(x)
⇒ y = 7/3 (x)
⇒ 3y - 7x = 0
or, 7x - 3y = 0
Hence, the function rule for the line that passes through the origin (0,0) and the point (-6,-14) is 7x - 3y = 0.
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