Answer: 9
Step-by-step explanation:
let the two points P (0,3) and Q(0,-6)
We need to find distance PQ
PQ=[tex]\sqrt{(x2-x1)^2+(y2-y1)^2}[/tex]
here
x1=x coordinate of P=0
y1=y coordinate of P=3
x2=x coordinate of Q=0
y2=y coordinate of Q=-6
Putting values
[tex]PQ=\sqrt{(0-0)^2+(-6-3)^2}\\[/tex][tex]PQ=\sqrt{(0)^2+(-9)^2} \\PQ=\sqrt{81} \\PQ=9[/tex]
