Answer:
Start with your basic equation for pH
pH = - log [H+]
then rearrange the equation to solve for [H+]
just like to get move something multiplied from the one side to the other you divide both sides by that number ( a*b = c …. a*b/b = c/b …. a = b/c), you do the ‘inverse’ of a log function, which is 10^
first bring the - over
-pH = log [H+]
then remove the log by taking 10^ on both sides
10^(-pH) = 10^(log [H+])
10^(-pH) = [H+]
and there is your relationship.
Explanation:
