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What is the molarity of a solution made from 0.250 mol of sodium hydroxide and 500 mL of water?



Answer :

Answer:

[tex]\boxed {\boxed {\sf 0.5 \ M \ NaOH}}[/tex]

Explanation:

Molarity is a measure of concentration in moles per liter.

[tex]molarity= \frac{moles}{liters}[/tex]

There are 0.250 moles of sodium hydroxide (NaOH) and 500 milliliters of water. We need to convert milliliters to liters. Remember that 1 liter contains 1000 milliliters.

[tex]\frac{1 \ L}{1000 \ mL}[/tex]

[tex]500 \ mL*\frac{1 \ L}{1000 \ mL}[/tex]

[tex]500*\frac{1 \ L}{1000 }[/tex]

[tex]\frac{500}{1000} \ L=0.5 \ L[/tex]

Now we have the values to solve for molarity:

  • moles= 0.250 mol NaOH
  • liters= 0.5 L

Substitute the values into the formula.

[tex]molarity= \frac{0.250 \ mol \ NaOH}{0.5 \ L}[/tex]

Divide.

[tex]molarity= 0.5 \ mol \ NaOH/ L[/tex]

  • 1 mole per liter (mol/liter) is equal to 1 Molar or M.
  • Our answer of 0.5 moles of sodium hydroxide per liter is equal to 0.5 M NaOH

[tex]molarity= 0.5 \ M \ NaOH[/tex]

The molarity of the solution is 0.5 M NaOH