Answered

Dilute nitric acid reacts with sodium carbonate solution. 2HNO3 (aq) + Na2CO3 (aq) → 2NaNO3 (aq) + H2O (l) + CO2 (g) 25.00 cm3 of sodium carbonate solution of concentration 0.153 mol/dm3 reacts completely with 25.3 cm3 of dilute nitric acid.


a) Calculate the number of moles of sodium carbonate.

b) Use your answer to (a) and the equation for the reaction to calculate the number of moles of nitric acid that reacted.

c) Use your answer to (b) to calculate the concentration of dilute nitric acid in mol/dm3.

d) Use your answer to (a), calculate the maximum volume (at r.t.p.) of carbon dioxide gas that could be produced in this reaction.



Answer :

venadana73
a) Mol = Conc x Vol
=0.153 x 0.025
= 0.003825 mol

b) HNO3 : Na2CO3
2 : 1
Moles of HNO3 = 0.00385 x 2
= 0.00765 mol

c) Conc = 0.00765 / 0.0253
= 0.3023715415 mol/dm^3

d) Vol of CO2 = 0.003825 x 24
= 0.0918 dm^3

Hope this helps! Im not 100% sure about the last one thoo.