By simplifying quadratic function [tex]f(x)= 5(x+4)^2-2[/tex] and comparing coefficient with standard form of quadratic function [tex]f(x) = ax^2 +bx+c[/tex] we got a = 5,b=40 and c=78
A function of the form [tex]f(x) = ax^2 + bx + c,[/tex] where a, b, and c are real numbers and a not equal to zero is known as quadratic function.
Given function is
[tex]f(x)= 5(x+4)^2-2[/tex]
We can covert it into standard form of quadratic function as
[tex]f(x)= 5( x^2+2\times x\times 4+4^2)-2\\\\\\\Rightarrow f(x)= 5( x^2+8x+16)-2\\\\\Rightarrow f(x)= 5 x^2+40x+80-2\\\\\\\\\Rightarrow f(x)= 5 x^2+40x+78\\\\\\[/tex]
Now we can get value of a ,b and c by comparing coefficient
[tex]f(x) = ax^2 +bx+c[/tex] with [tex]f(x)= 5 x^2+40x+78[/tex]
So a = 5,b=40 and c=78
By simplifying quadratic function [tex]f(x)= 5(x+4)^2-2[/tex] and comparing coefficient with standard form of quadratic function [tex]f(x) = ax^2 +bx+c[/tex] we got a = 5,b=40 and c=78
To learn more about quadratic function visit :https://brainly.com/question/4119784