Answer:
Step-by-step explanation:
#1
[tex]\frac{5x^2-5x}{x^2-2x+1}\\\frac{5x(x-1)}{(x-1)(x-1)}\\ \frac{5x}{x-1}[/tex]
#2
since it's negative, its npp (in the second part of the cubed factorization)
[tex]\frac{(x-2)(x^2+2x+4)}{(x^2-4)}\\\frac{(x-2)(x^2+2x+4)}{(x-2)(x+2)}\\ \\\frac{(x^2+2x+4)}{(x+2)}\\[/tex]
