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Given the equation 4x−8y=32, a second equation that forms a system with no solution is: 1. x−2y=8 2. x−2y=32 3. x+2y=8 4. 2x−y=32



Answer :

altavistard

Answer:

2. x−2y=32.3

Step-by-step explanation:

Given 4x - 8y = 32, a second equation that forms a system with no solution is most easily found by reducing the given equation to x - 2y = 8; we can then easily compare this x - 2y = 8 to x - 2y = 32.3.  These two lines are parallel and thus do not intercept, and thus the system has no solution.