B is closer to [tex]\frac{1}{2}[/tex].
Step-by-step explanation:
Given,
A⇒[tex]\frac{2}{15} +\frac{1}{3}[/tex]
B⇒[tex]\frac{6}{7}-\frac{1}{3}[/tex]
To find which is closer to [tex]\frac{1}{2}[/tex]
Now,
[tex]\frac{2}{15}+\frac{1}{3}[/tex]
= [tex]\frac{(2X1)+(1X5)}{15}[/tex]
= [tex]\frac{7}{15}[/tex] = 0.4666= 0.47
[tex]\frac{6}{7} -\frac{1}{3}[/tex]
= [tex]\frac{(6X3)-(1X7)}{21}[/tex]
= [tex]\frac{11}{21}[/tex] = 0.523
[tex]\frac{1}{2}[/tex] = 0.5
B is closer to [tex]\frac{1}{2}[/tex].
