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A force parallel to the x-axis acts on a particle moving along the x-axis. This force produces potential energy U(x) given by U(x)=αx4,where α = 0.750 J/m4J/m4.

# What is the magnitude of the force when the particle is at x = -0.800 m?

Express your answer with the appropriate units.



Answer :

Answer:

Explanation:

U(x)=αx⁴

Force F = - dU / dx

= 4αx³

= 4 x .75 x³

= 3 x³

Force when x = .8 m

F =  3 (0.8)³

= 1.54 N