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Suppose you cut a massless ideal spring in half. If the full spring had a force constant k, what is the force constant of each half, in terms of k? (Hint: Think of the original spring as two equal halves, each producing the same force as the entire spring. Do you see why the forces must be equal?)



Answer :

davidlcastiblanco

Answer:

The force for each half is:

[tex]F_2=2*K*L'[/tex]

Explanation:

The force of the spring is

[tex]F=K*L'[/tex]

now the massless is cut in half so now

[tex]L_2=\frac{L'}{2}[/tex]

so in terms in K the force is

[tex]K=\frac{F}{L'}[/tex]

[tex]K_2=\frac{F}{L_2}[/tex]

[tex]K_2=2*\frac{F}{L'}[/tex]

[tex]K_2=2*K[/tex]

[tex]F_2=2*K*L'[/tex]