a boy scout on top of a 1700 foot tall mountain spots a campsite. if he measures the angle of depression at 35°, how far is the campsite from the foot of the mountain



Answer :

Answer:

1190.35 ft

Step-by-step explanation:

The figure for the given scenario is shown below.

From the triangle Δ ABC, AB is the height of mountain, BC is the distance of campsite from the foot of mountain and [tex]\angle A[/tex] is the depression angle.

So, [tex]AB=1700\textrm{ ft},\angle A=35[/tex]°

Let the side BC be [tex]x[/tex] ft.

Now, the tan of the angle A is given as:

[tex]\tan (\angle A) =\frac{BC}{AB}[/tex]

Plug in [tex]x[/tex] for BC, 1700 ft for AB and 35° for [tex]\angle A[/tex]. Solve for [tex]x[/tex]. This gives,

[tex]\tan (35)=\frac{x}{1700}\\x=1700\times \tan (35)=1190.35\textrm{ ft}[/tex]

Therefore, the distance of campsite from the foot of the mountain is 1190.35 ft.

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